Tuesday, 12 April 2011

No 10126, Tuesday 12 Apr 11, Gridman

ACROSS
1   - Forsakes sinking Owens Ltd (4,4) - LETS DOWN*
5   - Oriental to declare belongings (6) - {E}{STATE}
9   - Good, in France a New Zealand ace gets a windfall (7) - {BON}{A}{NZ}{A}
10 - A short period to tear around the tower (7) - {MIN}{ARET*}
11 - Diaphanous treatment with nothing left on Sanskrit treatise (9) - UPANISHADo*
12 - Thanks to artist secreting a royal headgear (5) - {T{I}A}{RA}
13 - Woman's right — always! (4) - {EVE}{R}
14 - Logician strenuously tries a lot to beat totaliser (9) - ARISTOTLE*
17 - No duty is cast upon you to get such goods (3-6) - TAX-EXEMPT [CD]


19 - Beat first of wagon-horses with it (4) - {WH}IP Seems to be an error here (Addendum - {W}{HIP} - See comments)
23 - Shed tears as rice becomes rotten at the beginning of drought (5) - {CRIE*}{D}
24 - He gets high passes on the field from termagant, perhaps (6,3) - TARGET MAN*
25 - Become rigid if force is held by gun (7) - {ST{IF}{F}EN}
26 - Leader's foolish, losing 50 in a clamorous manner (7) - {NO1}{SIlLY}
27 - Polite word to satisfy? (6) - PLEASE [DD]
28 - But this expanse for planes is on the ground (8) - {AIR}{FIELD} &lit
DOWN
1   - Worker at science room more grim, having lost lid of dish (8) - {LAB}{dOURER}
2   - Got Anne worried by offering so much weight (7) - TONNAGE*
3   - Murdered an individual amidst noise (4,2) - {D{ONE} IN}
4   - Hit by the elements (7-6) - WEATHER-BEATEN [CD]
6   - Redraft contains final authorisation (8) - SANCTION*
7   - Post that's high up? (7) - AIRMAIL [CD]
8   - Catch partners losing money and sinking back (6) - srENTRAP <-
10 - Way of working in Latin (5,8) - MODUS OPERANDI [E]
15 - Adieu, Bye, Ciao, Farewell, Sayonara, Ta-ta… (4-4) - SEND-OFFS [E]
16 - On the look-out, not sleeping (4-4) - OPEN-EYED [DD]
18 - Kind of dye all the rage in a course in African history (7) - {A}{NIL{IN}E}
20 - Edge in fashion that has its ups and downs (7) - {HEM}{LINE} &lit
21 - Makes a scene and puts revised version after a chapter's beginning (4,2) - {A}{C}{TS UP*}
22 - What some maps show is on file that's set apart (6) - {RE}{LIEF*}



46 comments:

  1. 14 - Logician strenuously tries a lot to beat totaliser (9) - ARISTOTLE*

    I saw this as a double anagram

    Def Logician=Aristotle
    Strenuously=AInd
    fodder=tries a lot
    beat=Aind
    fodder=totaliser

    Initially put GOOD BYES in 15d and had a merry go round.

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  2. 14 - Logician strenuously tries a lot to beat totaliser (9) - ARISTOTLE*

    Anagram of TRIES A LOT as well as TOTALISER

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  3. What is the distinction if any between a CD and an &lit ?

    As I understand, if a clue is both the meaning and also the wordplay it becomes an &lit. So there could be an anagram&lit, hidden&lit, charade&lit etc.

    But would a CD&lit make sense?

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  4. On Bhavan's cue, how about AIRMAIL above?

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  5. I think today is one of Gridman's best in a while and certainly in this cycle, for me (disregarding the whip clue which seems to be an honest error).

    On the topic of &-lits and CD's, for what I have read, for a clue to be a proper &-lit each word in the clue should have a near equal part in the definition and in word play. I think I have read Tim Moorey write something to this effect somewhere. Seems to be as good a definition as any going around. Sticking to that def., it would seem that the Col. interprets &-lits a bit more loosely than the conventional sense. To me, ARISTOTLE would be a double anagram, AIRFIELD and HEMLINE would be very good CD's though one can argue HEMLINE as a semi-&lit. AIRMAIL is a CD as well to me.

    Anyone up for an alt. clue for WHIP to right the one blemish?

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  6. Noticed the increased use of 's in the last two puzzles.

    13 - Woman's right — always! (4)

    which expands to "woman is right" or "woman has right".

    In the first case "is" is a filler serving no purpose, but in the second "has" is a misleading container indicator.

    Not criticising, just an observation.

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  7. Be quick to defeat and criticise (4) WHIP (MD)

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  8. @Veer for a minute I misread your 'alt' and thought you were asking for an &lit clue for whip!

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  10. And people usually advocate the use of 'has' as a charade indicator more than as a container indicator.

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  11. Rouse with stylish woman on top? (4)

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  12. How come women are always involved in whip clues? ;-)

    Flog political enforcer (4)

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  13. starting with a joint,stir it (4)

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  14. Flog Captain's daughter (4)

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  15. Beat first of wagon-horses with it (4) - {WH}IP

    Could be W(agon-horses)+HIP ?
    (informal) With it = Hip = fashionable :)

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  16. Very simple puzzle today. Enjoyed. 8 D my COD

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  17. Ajeesh's 1202 seems bang on.

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  18. Good one Ajeesh. Veer will have to review his 09:04

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  19. [Insert Kishore's 08:36 here]

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  20. Your tax cartoon is very like our service tax officials. The Beggars Union here needs to take note.

    New ideas for Pranabda

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  21. Differential diagnosis, people.

    Ajeesh is invited to have a shot at yesterday's vase.

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  22. Suresh @13.54-
    As if he is short of ideas!

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  23. Not a good one if that is it.

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  24. Suresh 1430, Srividya said the same thing first, today morning at 1050 in yesterday's post ?!!! ;-)

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  25. Oh! I don't read yesterday's post today.

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  26. @Col, Missed the crossword yesterday. Lovely pic of asphodel, thank you.

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  27. No offence, Suresh, I ain't sending you to bed with the captain's daughter !

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  28. Ajeesh @1202 and Col. @1322, I think that is what Gridman intended. Nice crack, Ajeesh. The thought that crossed my mind briefly was if "it" = hip but I thought it would not be very it of Gridman to do so. But "with it" = hip does do the trick.

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  29. Off track question for Kishore, the resident mathemagician here or any other lurking math addicts as well:

    Last weekend I was messing around some Math homework of my 6th grade nephew. I was helping out with geometry and pointing him to solve a problem of figuring out internal angles subtended in a four sided figure. I then made up this comment that for any closed figure of n sides, the sum of all internal angles subtended by the vertices of the figure would be 180(n-2). I then very avuncularly asked him to prove it and indicated that the proof would be along the lines of proving that any closed figure with n sides can be broken down into n distinct triangles with two vertices of each triangle the same as that of the n-sided figure and one common vertex for all the triangles which would lie inside the closed n-sided figure. Is this true or am I just blowing smoke? How would one go about proving it? Thank you..

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  30. Veering off track with Veer:

    Of course it is true. Your smoke is not without fire. Simple proof is that the sum of all angles of the n triangles is 180xn degrees and reducing the 360 degrees subtended at the centre would make it 180n-360=180(n-2) degrees.

    Further, it is enough if we know 180 tables:

    For 3 sides 180

    Add 180 for each side added.

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  31. And the beauty is, you can chose any point within the closed figure to build your triangles.

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  32. In my 2040, please substitute 'point' for 'centre'.

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  33. While on mathemagics, today's question from one of my friends:

    What is the minimum value of 'x' so that x!, that is factorial of x ends with precisely fifty zero's, where 'x' is a positive integer ?

    Logical solving required, not brute force computronics.

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  34. OMG, that is 4d from yesterday !

    Adieu, Auf Wiedersehen, Bye, Ciao, Do Svidanya, Farewell, Kwaheri, Sayonara, Ta-ta for the day.

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  35. Hi Kishore

    Is the answer 205? Every multiple of 5^n, n belonging to the set of natural numbers, will generate an extra zero.

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  36. Bingo, Shyam:
    Number of trailing zeros for n!
    f(n)= Sigma (i=1tok) Abs(n/5^i), where k must be chosen so that 5^(k+1)<n<5^k

    Logical explanation:Seeing that having a multiple of 5 is essential for getting a zero (there are plenty of 2s lying around in every even number), we need to tract multiples of 5.There are 20 multiples of 5 in 100!, but of these 25,50, 75 and 100 yield two factors of 5 each, ie 4 more. Hence, 24 factors of 5 in 100!. When we think of 200!, 125 creeps in with 3 factors of 5 hence the number becomes 49. Hence, we require one more factor of 5 to make a round 50 which comes from 205. Hence, 205! is the answer.

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  37. And Veer, in a concave polygon, it would not always be possible to construct triangles to a point within. Eg: It is possible in a four sided arrowhead shape whereas impossible in a six sided Z shaped polygon.

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  38. @Kishore, Thx. Empirically it seems to make sense as far as I can see. I was wondering if there exists a proof that will extend to all n, where n are natural numbers >2. And I was also thinking if the other part of the statement about whether one can draw unique triangles with one common vertex inside any n-sided closed figure was true - your 2221 seems to indicate otherwise.

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  39. Veer
    I have come across something called the Art Gallery theorem, where essentially the problem is to find the position of minimum number of guards inside a polygon-shaped art gallery such that every point inside the polygon has a line-of-sight path to at least one guard.

    Essentially, one guard suffices for any convex polygon. But for complex shapes, it becomes a NP-hard problem!

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  40. @Shyam, 2305: Nice..Will check the Art Gallery Theorm out. I am a bit of a trivia buff storing tidbits here and there for use later though not on the scale of some here. Thx..

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